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n^2+4n-621=0
a = 1; b = 4; c = -621;
Δ = b2-4ac
Δ = 42-4·1·(-621)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-50}{2*1}=\frac{-54}{2} =-27 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+50}{2*1}=\frac{46}{2} =23 $
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